15x+50-5x^2=0

Solution for 15x+50-5x^2=0 equation:

15x+50-5x^2=0

a = -5; b = 15; c = +50;
Δ = b2-4ac
Δ = 152-4·(-5)·50
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-35}{2*-5}=\frac{-50}{-10}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+35}{2*-5}=\frac{20}{-10}
=-2
$